(2x-3)(x^2-5x+6)=0

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Solution for (2x-3)(x^2-5x+6)=0 equation:


Simplifying
(2x + -3)(x2 + -5x + 6) = 0

Reorder the terms:
(-3 + 2x)(x2 + -5x + 6) = 0

Reorder the terms:
(-3 + 2x)(6 + -5x + x2) = 0

Multiply (-3 + 2x) * (6 + -5x + x2)
(-3(6 + -5x + x2) + 2x * (6 + -5x + x2)) = 0
((6 * -3 + -5x * -3 + x2 * -3) + 2x * (6 + -5x + x2)) = 0
((-18 + 15x + -3x2) + 2x * (6 + -5x + x2)) = 0
(-18 + 15x + -3x2 + (6 * 2x + -5x * 2x + x2 * 2x)) = 0
(-18 + 15x + -3x2 + (12x + -10x2 + 2x3)) = 0

Reorder the terms:
(-18 + 15x + 12x + -3x2 + -10x2 + 2x3) = 0

Combine like terms: 15x + 12x = 27x
(-18 + 27x + -3x2 + -10x2 + 2x3) = 0

Combine like terms: -3x2 + -10x2 = -13x2
(-18 + 27x + -13x2 + 2x3) = 0

Solving
-18 + 27x + -13x2 + 2x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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